\(\int \frac {\text {arcsinh}(a x)^2}{x^2} \, dx\) [18]

   Optimal result
   Rubi [A] (verified)
   Mathematica [A] (verified)
   Maple [A] (verified)
   Fricas [F]
   Sympy [F]
   Maxima [F]
   Giac [F]
   Mupad [F(-1)]

Optimal result

Integrand size = 10, antiderivative size = 50 \[ \int \frac {\text {arcsinh}(a x)^2}{x^2} \, dx=-\frac {\text {arcsinh}(a x)^2}{x}-4 a \text {arcsinh}(a x) \text {arctanh}\left (e^{\text {arcsinh}(a x)}\right )-2 a \operatorname {PolyLog}\left (2,-e^{\text {arcsinh}(a x)}\right )+2 a \operatorname {PolyLog}\left (2,e^{\text {arcsinh}(a x)}\right ) \]

[Out]

-arcsinh(a*x)^2/x-4*a*arcsinh(a*x)*arctanh(a*x+(a^2*x^2+1)^(1/2))-2*a*polylog(2,-a*x-(a^2*x^2+1)^(1/2))+2*a*po
lylog(2,a*x+(a^2*x^2+1)^(1/2))

Rubi [A] (verified)

Time = 0.07 (sec) , antiderivative size = 50, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {5776, 5816, 4267, 2317, 2438} \[ \int \frac {\text {arcsinh}(a x)^2}{x^2} \, dx=-4 a \text {arcsinh}(a x) \text {arctanh}\left (e^{\text {arcsinh}(a x)}\right )-2 a \operatorname {PolyLog}\left (2,-e^{\text {arcsinh}(a x)}\right )+2 a \operatorname {PolyLog}\left (2,e^{\text {arcsinh}(a x)}\right )-\frac {\text {arcsinh}(a x)^2}{x} \]

[In]

Int[ArcSinh[a*x]^2/x^2,x]

[Out]

-(ArcSinh[a*x]^2/x) - 4*a*ArcSinh[a*x]*ArcTanh[E^ArcSinh[a*x]] - 2*a*PolyLog[2, -E^ArcSinh[a*x]] + 2*a*PolyLog
[2, E^ArcSinh[a*x]]

Rule 2317

Int[Log[(a_) + (b_.)*((F_)^((e_.)*((c_.) + (d_.)*(x_))))^(n_.)], x_Symbol] :> Dist[1/(d*e*n*Log[F]), Subst[Int
[Log[a + b*x]/x, x], x, (F^(e*(c + d*x)))^n], x] /; FreeQ[{F, a, b, c, d, e, n}, x] && GtQ[a, 0]

Rule 2438

Int[Log[(c_.)*((d_) + (e_.)*(x_)^(n_.))]/(x_), x_Symbol] :> Simp[-PolyLog[2, (-c)*e*x^n]/n, x] /; FreeQ[{c, d,
 e, n}, x] && EqQ[c*d, 1]

Rule 4267

Int[csc[(e_.) + (Complex[0, fz_])*(f_.)*(x_)]*((c_.) + (d_.)*(x_))^(m_.), x_Symbol] :> Simp[-2*(c + d*x)^m*(Ar
cTanh[E^((-I)*e + f*fz*x)]/(f*fz*I)), x] + (-Dist[d*(m/(f*fz*I)), Int[(c + d*x)^(m - 1)*Log[1 - E^((-I)*e + f*
fz*x)], x], x] + Dist[d*(m/(f*fz*I)), Int[(c + d*x)^(m - 1)*Log[1 + E^((-I)*e + f*fz*x)], x], x]) /; FreeQ[{c,
 d, e, f, fz}, x] && IGtQ[m, 0]

Rule 5776

Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_.)*((d_.)*(x_))^(m_.), x_Symbol] :> Simp[(d*x)^(m + 1)*((a + b*ArcS
inh[c*x])^n/(d*(m + 1))), x] - Dist[b*c*(n/(d*(m + 1))), Int[(d*x)^(m + 1)*((a + b*ArcSinh[c*x])^(n - 1)/Sqrt[
1 + c^2*x^2]), x], x] /; FreeQ[{a, b, c, d, m}, x] && IGtQ[n, 0] && NeQ[m, -1]

Rule 5816

Int[(((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_.)*(x_)^(m_))/Sqrt[(d_) + (e_.)*(x_)^2], x_Symbol] :> Dist[(1/c^(m
 + 1))*Simp[Sqrt[1 + c^2*x^2]/Sqrt[d + e*x^2]], Subst[Int[(a + b*x)^n*Sinh[x]^m, x], x, ArcSinh[c*x]], x] /; F
reeQ[{a, b, c, d, e}, x] && EqQ[e, c^2*d] && IGtQ[n, 0] && IntegerQ[m]

Rubi steps \begin{align*} \text {integral}& = -\frac {\text {arcsinh}(a x)^2}{x}+(2 a) \int \frac {\text {arcsinh}(a x)}{x \sqrt {1+a^2 x^2}} \, dx \\ & = -\frac {\text {arcsinh}(a x)^2}{x}+(2 a) \text {Subst}(\int x \text {csch}(x) \, dx,x,\text {arcsinh}(a x)) \\ & = -\frac {\text {arcsinh}(a x)^2}{x}-4 a \text {arcsinh}(a x) \text {arctanh}\left (e^{\text {arcsinh}(a x)}\right )-(2 a) \text {Subst}\left (\int \log \left (1-e^x\right ) \, dx,x,\text {arcsinh}(a x)\right )+(2 a) \text {Subst}\left (\int \log \left (1+e^x\right ) \, dx,x,\text {arcsinh}(a x)\right ) \\ & = -\frac {\text {arcsinh}(a x)^2}{x}-4 a \text {arcsinh}(a x) \text {arctanh}\left (e^{\text {arcsinh}(a x)}\right )-(2 a) \text {Subst}\left (\int \frac {\log (1-x)}{x} \, dx,x,e^{\text {arcsinh}(a x)}\right )+(2 a) \text {Subst}\left (\int \frac {\log (1+x)}{x} \, dx,x,e^{\text {arcsinh}(a x)}\right ) \\ & = -\frac {\text {arcsinh}(a x)^2}{x}-4 a \text {arcsinh}(a x) \text {arctanh}\left (e^{\text {arcsinh}(a x)}\right )-2 a \operatorname {PolyLog}\left (2,-e^{\text {arcsinh}(a x)}\right )+2 a \operatorname {PolyLog}\left (2,e^{\text {arcsinh}(a x)}\right ) \\ \end{align*}

Mathematica [A] (verified)

Time = 0.17 (sec) , antiderivative size = 75, normalized size of antiderivative = 1.50 \[ \int \frac {\text {arcsinh}(a x)^2}{x^2} \, dx=a \left (-\text {arcsinh}(a x) \left (\frac {\text {arcsinh}(a x)}{a x}-2 \log \left (1-e^{-\text {arcsinh}(a x)}\right )+2 \log \left (1+e^{-\text {arcsinh}(a x)}\right )\right )+2 \operatorname {PolyLog}\left (2,-e^{-\text {arcsinh}(a x)}\right )-2 \operatorname {PolyLog}\left (2,e^{-\text {arcsinh}(a x)}\right )\right ) \]

[In]

Integrate[ArcSinh[a*x]^2/x^2,x]

[Out]

a*(-(ArcSinh[a*x]*(ArcSinh[a*x]/(a*x) - 2*Log[1 - E^(-ArcSinh[a*x])] + 2*Log[1 + E^(-ArcSinh[a*x])])) + 2*Poly
Log[2, -E^(-ArcSinh[a*x])] - 2*PolyLog[2, E^(-ArcSinh[a*x])])

Maple [A] (verified)

Time = 0.05 (sec) , antiderivative size = 108, normalized size of antiderivative = 2.16

method result size
derivativedivides \(a \left (-\frac {\operatorname {arcsinh}\left (a x \right )^{2}}{a x}-2 \,\operatorname {arcsinh}\left (a x \right ) \ln \left (1+a x +\sqrt {a^{2} x^{2}+1}\right )-2 \operatorname {polylog}\left (2, -a x -\sqrt {a^{2} x^{2}+1}\right )+2 \,\operatorname {arcsinh}\left (a x \right ) \ln \left (1-a x -\sqrt {a^{2} x^{2}+1}\right )+2 \operatorname {polylog}\left (2, a x +\sqrt {a^{2} x^{2}+1}\right )\right )\) \(108\)
default \(a \left (-\frac {\operatorname {arcsinh}\left (a x \right )^{2}}{a x}-2 \,\operatorname {arcsinh}\left (a x \right ) \ln \left (1+a x +\sqrt {a^{2} x^{2}+1}\right )-2 \operatorname {polylog}\left (2, -a x -\sqrt {a^{2} x^{2}+1}\right )+2 \,\operatorname {arcsinh}\left (a x \right ) \ln \left (1-a x -\sqrt {a^{2} x^{2}+1}\right )+2 \operatorname {polylog}\left (2, a x +\sqrt {a^{2} x^{2}+1}\right )\right )\) \(108\)

[In]

int(arcsinh(a*x)^2/x^2,x,method=_RETURNVERBOSE)

[Out]

a*(-arcsinh(a*x)^2/a/x-2*arcsinh(a*x)*ln(1+a*x+(a^2*x^2+1)^(1/2))-2*polylog(2,-a*x-(a^2*x^2+1)^(1/2))+2*arcsin
h(a*x)*ln(1-a*x-(a^2*x^2+1)^(1/2))+2*polylog(2,a*x+(a^2*x^2+1)^(1/2)))

Fricas [F]

\[ \int \frac {\text {arcsinh}(a x)^2}{x^2} \, dx=\int { \frac {\operatorname {arsinh}\left (a x\right )^{2}}{x^{2}} \,d x } \]

[In]

integrate(arcsinh(a*x)^2/x^2,x, algorithm="fricas")

[Out]

integral(arcsinh(a*x)^2/x^2, x)

Sympy [F]

\[ \int \frac {\text {arcsinh}(a x)^2}{x^2} \, dx=\int \frac {\operatorname {asinh}^{2}{\left (a x \right )}}{x^{2}}\, dx \]

[In]

integrate(asinh(a*x)**2/x**2,x)

[Out]

Integral(asinh(a*x)**2/x**2, x)

Maxima [F]

\[ \int \frac {\text {arcsinh}(a x)^2}{x^2} \, dx=\int { \frac {\operatorname {arsinh}\left (a x\right )^{2}}{x^{2}} \,d x } \]

[In]

integrate(arcsinh(a*x)^2/x^2,x, algorithm="maxima")

[Out]

-log(a*x + sqrt(a^2*x^2 + 1))^2/x + integrate(2*(a^3*x^2 + sqrt(a^2*x^2 + 1)*a^2*x + a)*log(a*x + sqrt(a^2*x^2
 + 1))/(a^3*x^4 + a*x^2 + (a^2*x^3 + x)*sqrt(a^2*x^2 + 1)), x)

Giac [F]

\[ \int \frac {\text {arcsinh}(a x)^2}{x^2} \, dx=\int { \frac {\operatorname {arsinh}\left (a x\right )^{2}}{x^{2}} \,d x } \]

[In]

integrate(arcsinh(a*x)^2/x^2,x, algorithm="giac")

[Out]

integrate(arcsinh(a*x)^2/x^2, x)

Mupad [F(-1)]

Timed out. \[ \int \frac {\text {arcsinh}(a x)^2}{x^2} \, dx=\int \frac {{\mathrm {asinh}\left (a\,x\right )}^2}{x^2} \,d x \]

[In]

int(asinh(a*x)^2/x^2,x)

[Out]

int(asinh(a*x)^2/x^2, x)